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ELEN [110]
3 years ago
12

Can someone help me ASAP please. I'll give extra points if right fr

Mathematics
1 answer:
9966 [12]3 years ago
6 0

Answer:

y = -1/4x + -6

Step-by-step explanation:

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Which is the least positive integer that should be multiplied with 2 × 2 × 2 × 3 so that we get
Elan Coil [88]

Answer:

3

Step-by-step explanation:

In order to have a perfect square you have to have at least two prime factors, and since three is quite clearly not in a pair, the answer is three.

8 0
3 years ago
The width of a rectangle is 1 less than one-half its length, and the perimeter is 46.
RideAnS [48]
1)x+1/2x-1=46
2) The length is 94/3(or 31 1/3) and the width is 44/3(or 14 2/3)
6 0
3 years ago
A movie theater charges $15 for standard viewing, $20 for 3D viewing, and $35 for Dinner and a
Ludmilka [50]

The quantity of each type of seats sold are as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.

That is, x = 4y

Also, total seats

= (x) + (y) + (z) = 3000...….............eqn(1)

Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.

  • 20x + 35y + 15z = 53000...........eqn(2)

By substituting 4y for x in equations 1 and 2; we have;

<em>5y + z = 3000</em>..…........eqn(3) and

<em>115y + 15z = 53000</em>.........eqn(4)

By solving equations 3 and 4 simultaneously; we have;

y = 200 and z = 2000

and since x = 4y

x = 800

The quantity of each type of seats sold is as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

Read more:

brainly.com/question/12413726

5 0
3 years ago
You have a 5” by 7” photo that you would like to have enlarged to fit an 8” by 10” frame. Would the two photographs be similar?
Rasek [7]
No, 2 of the 5x7 would actually take up. 10x14
8 0
3 years ago
Of the 32 students in a certain class, 15 are in a music club and 20 are in a dance club. if 10 of the students are not in eithe
mel-nik [20]
There are a total of 35 in the two clubs and 10 not in either. That makes 45 students, however there are only 32 in the class which means 45-32 = 13 students in BOTH clubs. So if we want to find how many are in only one club we can say 32 = 13 + 10 + x

x = 9 students in only one club
8 0
3 years ago
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