All categories

3 years ago

Please help taking test rn

Mathematics

1 answer:

True [87]3 years ago

7 0

Answer:

Drop Down 1:

Volume

Drop Down 2:

Day

You might be interested in

In each figure below find m ∠1 and m∠2, if a||b. Justify with<br> reasons your solution.

Mazyrski [523]

Answer:

m<1 = 130°

m<2 = 50°

Step-by-step explanation:

Since given that line a is parallel to line b, and <1 and 130° are interior angles that alternate each other, therefore:

m<1 = 130° (alternate interior angle theorem)

Also,

130° and <2 lie on same side inside the parallel lines cut across by the transversal, therefore,

m<2 + 130° = 180° (same side interior angles theorem)

m<2 = 180° - 130°

m<2 = 50°

6 0

3 years ago

Building a has 7,500 ft of an office space for 320 employees building b has 9,500 square feet of office space for 370 employees

iren2701 [21]

Answer:

I believe the correct answer is Building B

Step-by-step explanation:

Building A is 23.45 per employee and Building B is 25.67 per employee

4 0

3 years ago

if the hieght and radius of the cone is tripled then find the ratio of Volume of the new cone and of that of original

solniwko [45]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=\stackrel{3\times r}{3r}\\
h=\stackrel{3\times h}{3h}
\end{cases}\implies V=\cfrac{\pi (3r)^2(3h)}{3}
\\\\\\
V=\cfrac{\pi (3^2r^2)(3h)}{3}\implies V=\cfrac{\pi (9r^2)(3h)}{3}\implies V=27\left( \cfrac{\pi r^2 h}{3} \right)$

notice the original, and the new one, with the tripled "r" and "h" is just, whatever the original was times 27, namely 27 times as large as the original.

6 0

3 years ago

Ok, is 0 really a number? It is neither a negative or a positive number, you never count starting on 0, and its not a even numbe

Kisachek [45]

Answer: 0 is a number though it is not an even or an odd number we have to count from zero always 0 is always the first number. 0 is also a whole number

I hope I helped

4 0

2 years ago

Read 2 more answers

Solve the following system of equations by the substitution method.

ruslelena [56]

5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 → $x = \frac{y+6}{5}$

Soon:
2x - 3y = 4 → $2* (\frac{y+6}{5}) - 3y = 4\to \frac{2y+12}{5} - 3y = 4$
<span>least common multiple (5)
</span> $\frac{2y+12}{5} - 3y = 4\to \frac{2y+12}{\diagup\!\!\!\!\!5} - \frac{15y}{\diagup\!\!\!\!\!5} = \frac{20}{\diagup\!\!\!\!\!5}$
$2y + 12 - 15y = 20$
$- 15y + 2y = 20 - 12$
$- 13y = 8$
$\boxed{\boxed{y = - \frac{8}{13} }}\end{array}}\qquad\quad\checkmark$

4 0

4 years ago