A= bh(1/2)
a=12(14)(1/2)
a= 168(1/2)
a= 84inches
First we will find the number of integers between 301 and 400 that are multiples of 4. We can see that the first such number is 304 being a multiple of 4. So the required numbers are 304, 308, 312,...,400 which form an AP.
To find the number of such integers use,
. Here is the nth term, is the common difference of the AP. Here its is . So
The required sum of the AP is
Answer:
3,765.2
Step-by-step explanation:
Move the decimal to the tenths place.