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Vitek1552 [10]
3 years ago
11

What is the probability that the sun will rise tommorow?​

Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

100 percent the sun will rise tomorrow but who is to say you will get to see the sun tomorrow? who is to say you won't have a heart attack and die on this material planet tomorrow and won't get to see the sun rise. or what if the sun sends out a solar flare and burns everyone to a crisp and completely demolishes our ozone layer allowing oxygen to excrete from the planet and cooking everyone with solar radiation all at the same time catastrophic winds and earthquakes demolish the planet because of loss of pressure from the gravity field held in check by the oxygen that has left the planet from a destroyed ozone layer leaving everyone to suffocate and die and excruciating death therefore yes the sun will rise tomorrow but certain events are to unfold we could never prognosticate

Step-by-step explanation:

EastWind [94]3 years ago
3 0

Answer:

100°/•

Step-by-step explanation:

the sun doesn't necessarily rise , it is the earth rotating while revolving around the sun so it the only chance of the sun not "rising" is if earth stopped rotating and revolving around the sun and the chances of earth stoping revolving or rotating or very low

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Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
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