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3 years ago

On paper, use the completing the square method to solve the equation x^2 + 16x + 2. Can anyone help me with this?

Mathematics

1 answer:

scoray [572]3 years ago

6 0

Answer:

x = -8 ± √62

Step-by-step explanation:

An equation needs an equals sign. I assume the expression equals zero?

x² + 16x + 2 = 0

To complete the square, start by making the leading coefficient 1 (which it already is).

Next, take half of the b coefficient, square it, and add the result to both sides.

(16/2)² = 8² = 64

x² + 16x + 64 + 2 = 64

Factor the perfect square:

(x + 8)² + 2 = 64

Solve for x:

(x + 8)² = 62

x + 8 = ±√62

x = -8 ± √62

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What is the simplified form of 4r + 5s – 16r + 3s?

irakobra [83]

Hello!

You can only combine numbers with the same variable

4r - 16r = -12r
5s + 3s = 8s

The answer is -12r + 8s

Hope this helps!

8 0

3 years ago

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A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l

tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

Step(ii):-

The Empirical rule

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }$

Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = P(Z≥2.383)

= 1- P( Z<2.383)

= 1-( 0.5 -+A(2.38))

= 0.5 - A(2.38)

= 0.5 -0.4913

= 0.0087

Final answer:-

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0

3 years ago

I need help with this question!

KonstantinChe [14]

F(x)=2x^4 is the answer

5 0

3 years ago

Jessica rides the bus 8% miles each day.how many miles does she ride in 10 days?

liq [111]

Answer:

80 miles

Step-by-step explanation:

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2 years ago

Which function has an asymptote at x= 39

LekaFEV [45]

Answer:

option B : $f(x)= log_7(x-39)$

Step-by-step explanation:

(a) $f(x) = 7^{x-39}$

For exponential function , there is no vertical asymptotes

General form of exponential function is

$f(x) = n^{ax-b}+k$

$f(x) = 7^{x-39}$

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

$f(x)= log_7(x-39)$

To find vertical asymptote we set the argument of log =0 and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39

3 0

3 years ago

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