Ask question

Ask question

All categories

3 years ago

11

Tessa bought stock in a restaurant for $126.00. Her stock is now worth $163.80. What is the percentage increase of the value of

Tessa's stock?

1 answer:

ololo11 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

stream walls by louis tomlinson on itunes

You might be interested in

Find the mean of the data

Triss [41]

<h3>Answer: 6.282</h3>

Explanation:

Refer to the table below. I've added a third row where I multiplied each x value with its corresponding frequency value f. We can refer to this row as the xf row.

Once we know the xf values, we add them up to get 245.

We'll then divide that result over the sum of the frequency values (add everything in the second row). The sum of the frequency values is 39.

So the mean is approximately: 245/39 = 6.282051 which rounds to 6.282

Notice that this mean value is fairly close to the x value which has the highest frequency.

5 0

3 years ago

maxonik [38]

Answer:

x=13

OR

x=-13 and 13

hmm I think

8 0

3 years ago

Read 2 more answers

What is the value of cos(tan-1(0))?<br><br> –1<br> 0<br> 1<br> StartFraction pi Over 2 EndFraction

djyliett [7]

Answer:

answer is 1

Step-by-step explanation:

just did test on edge

4 0

3 years ago

*****50 POINTSSSS*****

defon

Answer:

<h3>Given</h3>

m∠REG = 78°
mAR = 46°
ER ≅ GA

<h3>Solution</h3>

m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
m∠TAR = 1/2mAR = 1/2(46°) = 23° (tangent chord angle is half the size of intercepted arc)
m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
mAG = 2m∠GAN = 2(55°) = 110°
mRE = mAG = 110° (as ER ≅ GA)
mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)

6 0

3 years ago

5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls

miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = $cos^{2}x - sin^{2}x$

2. Pythagorean identity:

$cos^{2}x + sin^{2}x = 1$

Back to your problem, replacing the variable by the above:

$5cosx-sin\frac{x}{2}+7 = 0$

$5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Double-angle formula

$5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Pythagorean identity

Given $y = \frac{x}{2}$

$5(1-2sin^{2}y) - 2siny + 7 = 0$

$10sin^{2}y+2siny-12=0$

$5sin^{2}y+siny-6=0$

$(5siny + 6)(siny - 1)=0$ , we know -1 < sinx < 1, for every x ∈ R

$siny = 1, y =90$

$y = \frac{x}{2}$

$x = 180$

8 0

3 years ago