The measure of < JKL = 25+25 = 50 degrees.
Angle JOK = 360 -230 = 130 degrees , (where O is the center of the circle)
< OLK = < OJK = 90 degrees ( tangent to a circle)
< LOK = < JOK = 180 - (90+65) = 180 - 155 = 25 degrees
The solution is: < JKL = 25 +25 = 50 degrees
Let us write vertices of the given rectangle are PQRS.
Where Q is (c,d) and S is (a,b).
a) Now, we need to find the coordinates of P and R points.
x-coordinate for P is a and y-coordinate of P is d.
<h3>Therefore P is (a,d).</h3>On the same way, x-coordinate for R is c and y-coordinate of R is b.
<h3>Therefore R is (d,b).</h3>b) <em>Width of the rectangle is difference of y-coordinates of P and S points</em>.
<h3>Therefore, width = b - d.</h3>
Answer:
Step-by-step explanation:
1.
all the lines with slope 2 are parallel with each-other
all the lines with slope 1/3 are parallel with each-other
2.
all lines have positive slope so they go upward from left to right
3.
slope 2 is steeper then slope 1/3
4.
the distance between the parallel lines with slope (1/3) is greater for the lines with the slope 2
