Answer:
solution given:
let's see only in a right-angled triangle Δ ACD.
AC=3 units
AD=5 units
since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

25=9+
=25-9=16

Now
Area of rectangle Δ ACD=
similarly,

since AB=CE=2.4 units
Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

now
area of trapezoid=area ofΔACD+Area of ΔABC
=6+
Answer:
m= -12
Step-by-step explanation:
assuming it is solve for m
The answer would be 92 by 92. Rectangular area only refers to the shape of the area. Squares are special types of rectangles.
368/4 equals 92.
I divided by 4 because a rectangle has four sides.
((–7) + (3 + i)) - (2 - (6 + i)) =-9 + 9 i