Move the decimal 6 times to the right (when it's negative) and make sure to put 0's.
Answer: 3582000.
:)
Answer: The speed of the boat in still water is 6.5 mph.
The speed of the current is 2.5 mph
Step-by-step explanation:
Let x represent the speed of the boat in still water.
Let y represent the speed of the current.
A boat going upstream on The River averages 4 mph. Assuming it travelled against the current while going upstream, its total speed would be (x - y) mph. It means that
x - y = 4- - - - - - - - - - - -1
Going downstream, the boat averages 9 mph. Assuming it travelled with the current while going upstream, its total speed would be (x + y) mph. It means that
x + y = 9- - - - - - - - - - - -2
Adding both equations, it becomes
2x = 13
x = 13/2
x = 6.5 mph
Substituting x = 6.5 into equation 1, it becomes
6.5 - y = 4
y = 6.5 - 4
y = 2.5 mph
so that means one of the relevant sides of the cylinders, namely the height, are on a 2:3 ratio, or 2/3 for that matter.
![\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B5em%7D%20%5Ctextit%7Bratio%20relations%20of%20two%20similar%20shapes%7D%20%5C%5C%5B2em%5D%20%5Cbegin%7Barray%7D%7Bccccllll%7D%20%26%5Cstackrel%7Bratio~of~the%7D%7BSides%7D%26%5Cstackrel%7Bratio~of~the%7D%7BAreas%7D%26%5Cstackrel%7Bratio~of~the%7D%7BVolumes%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%26%5Ccfrac%7Bs%7D%7Bs%7D%26%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%26%5Ccfrac%7Bs%5E3%7D%7Bs%5E3%7D%20%5Cend%7Barray%7D%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\stackrel{\textit{ratio of the}}{sides}}{\cfrac{2}{3}}~\hspace{7em}\stackrel{\stackrel{\textit{ratio of the}}{volumes}}{\cfrac{2^3}{3^3}}\implies \cfrac{8}{27}\implies 8:27](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%5Cqquad%20%5Ccfrac%7Bs%7D%7Bs%7D%3D%5Ccfrac%7B%5Csqrt%7Bs%5E2%7D%7D%7B%5Csqrt%7Bs%5E2%7D%7D%3D%5Ccfrac%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bratio%20of%20the%7D%7D%7Bsides%7D%7D%7B%5Ccfrac%7B2%7D%7B3%7D%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bratio%20of%20the%7D%7D%7Bvolumes%7D%7D%7B%5Ccfrac%7B2%5E3%7D%7B3%5E3%7D%7D%5Cimplies%20%5Ccfrac%7B8%7D%7B27%7D%5Cimplies%208%3A27)
Answer:
rate of change: 15 pages per day
initial value: 50 pages
Step-by-step explanation:
In this scenario, the rate of change is 15 pages per day. This means that every single day Angelica can read 15 pages of the book and that is the number by which her total read pages will change. In 10 days Angelica can read 150 pages (10 days * 15 pages per day). Since the question states that in 10 days Angelica has read 200 pages then this means that the initial value of pages read would be 50 since this would be the number of missing pages to obtain the 200 read pages in a span of 10 days...
200 - 150 = 50 pages.
Answer:
i think x would be 0.8
sorry if im wrong :( its been awhile since ive done this stuff
Step-by-step explanation:
