My answer is the 2nd option.
Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.
Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB.
Answer:
https://classcalc.com/graphing-calculator/share/fJcbqPoXEobek5Lm6/untitled-calc
Step-by-step explanation:
x y=6x+12
-1 6
0 12
2 24
4 36
6 48
8 60
Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 
Answer:
The equation of the line that is <em>perpendicular</em> to <em>y = 2x + 2</em> is
<em>y = -1/2x</em>
Step-by-step explanation:
The original equation is y = 2x + 2; it's slope is <em>2</em>
Any line perpendicular to this equation would have to have a slope that is the negative reciprocal of the original slope.
Example:
y = 2x + 2 so,
the perpendicular line's slope must be -1/2
Write a new equation with the new slope:
y = -1/2x + b
We know that this line passes through (8, -4)
Plug these coordinates in the equation to find b, the y-intercept
-4 = -1/2 (8) + b
-4 = -4 + b
0 = b
b = 0
We do not have to write y = -1/2x + 0
So, our final answer is "y = -1/2x is perpendicular to y = 2x+2"
Answer:
<span>x=<span><span>5±<span>√41</span></span>4</span></span>
Explanation:
<span>2<span>x2</span>−5x+1=3</span>
<span><span>aaaaaaa</span>−3a−3<span>aaa</span></span>Subtract 3 from both sides
<span>2<span>x2</span>−5x−2=0</span>
This equation is not factorable, so use the quadratic formula.
<span>x=<span><span>−b±<span>√<span><span>b2</span>−4ac</span></span></span><span>2a</span></span><span>aaa</span></span> for<span><span>aaa</span>a<span>x2</span>+bx+c=0</span>
<span>a=2,b=−5,c=−2</span>
<span>x=<span><span>−<span>(−5)</span>±<span>√<span><span><span>(−5)</span>2</span>−4<span>(2)</span><span>(−2)</span></span></span></span><span>2⋅2</span></span></span>
<span>x=<span><span><span>5±<span>√41</span></span>4</span></span></span>
hope this helped :)
alisa202
