Can someone please help me ASAP
1 answer:
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR = = 17
You might be interested in
Answer:
(1)
Multiplying by 3 both sides of the equality you get that
3u is in the Span of the vectors .
(2)
That's not true, consider the following counter example.
is a linear combination of
but is NOT a linear combination of
Step-by-step explanation:
(1)
As the hint indicates, you know that
Then, if you multiply both sides of the equality by 3, you get that
And that's it. 3u is in the Span of the vectors
(2)
That's not true, consider the following counter example.
is a linear combination of
but is NOT a linear combination of