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Feliz [49]
2 years ago
5

The freezing point of neon is about -249c . The freezing point of chorine is about 148c higher. What is the approximate freezing

point of chlorine?
Mathematics
1 answer:
Westkost [7]2 years ago
5 0

Answer:

-101 c.

Step-by-step explanation:

-249 + 148

= -(249 - 148)

= -101 C.

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Solve using long division<br> (x² – 3x - 40) + (x+5)
wolverine [178]

The chosen topic is not meant for use with this type of problem.

However, if you simplify it, your answer is:

x^2 − 2x − 35

4 0
2 years ago
Read 2 more answers
3) 8p + 7q = 43<br>2 -7=-q<br>how can I solve this with substitution?​
Bess [88]

Answer:

p=1, q=5. (1, 5).

Step-by-step explanation:

8p+7q=43

2-7=-q

------------------

-q=-5

q=5

--------

8p+7(5)=43

8p+35=43

8p=43-35

8p=8

p=8/8=1

6 0
2 years ago
Please help me with this pleaseee
torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = \frac{opposite}{adjacent} = \frac{500}{x}

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = \frac{500}{tan80} ≈ 88.2

5 0
3 years ago
Sharon buys 14 folders for 0.75 dollars each how much change she will
AlekseyPX
0.75 x 14 = 10.50
15 - 10.50 = 4.50
your answer is : Sharon will receive $4.50 change
7 0
3 years ago
In a graphing program, graph the following 4 functions in the same coordinate plane.
9966 [12]

See below for the changes when the exponential function is transformed

<h3>How to determine the effect of a</h3>

The exponential functions are given as:

y = \sqrt x

y = 5\sqrt x

y = 14\sqrt{x

y = -2\sqrt{x

An exponential function of the above form is represented as:

y = a\sqrt{x

See attachment for the graph of the four functions.

<u>When a is large</u>

This is represented by y = 14\sqrt{x

In this case, the curve of the base form y = \sqrt x is vertically stretched and it moves closer to the y-axis

<u>When a is small</u>

This is represented by y = 5\sqrt x

In this case, the curve of the base form y = \sqrt x is vertically stretched and it moves away from the x-axis

<u>When a is negative</u>

This is represented by y = -2\sqrt{x

In this case, the curve of the base form y = \sqrt x is vertically stretched and is reflected across the y-axis.

Read more about function transformation at:

brainly.com/question/26896273

#SPJ1

5 0
2 years ago
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