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lbvjy [14]
3 years ago
9

Please help me with this question I really need help!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

Step-by-step explanation:

The angles of a triangle add up to 180°.

∠4 = 180°-35°-90° = 55°

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If you borrow $100 for 3 years with an annual interest rate of 9% how much will you pay altogether.
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Write and solve an equation for the relationship described below. Four times a number plus three is the same as five plus the nu
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<span>Answer: 4*x+3=5+x
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3 years ago
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
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one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

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