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irinina [24]
2 years ago
12

Markley's birthday party will cost $22.50 if she invites four of her friends. If she adds one

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
4 0

Answer:

The party will cost 28.125 dollars.

Step-by-step explanation:

Because to find how much each person costs you would have to take 22.50 divided by 4 to get 5.625, then do 5.625 times 5 to get 28.125 as your answer.

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I need help on question 5. It’s probably easy for some of you :))
IRINA_888 [86]

okay,do you know how to do long division...if you do but your having chroble just right it out on a paper you need all the mutiples of 13

13,26,39,52,65,78,91,104,117,130,143,156,169,182,195,208,221,234,247,260,273,286,299,312,325,338,351,364,377,390,403,416,429,442,455,468,481,494,507,520,533,546,559,572,585,598,611,624,637,

just keep adding 13

at the step it showes your a it looks like u need to see how many times 13 can go into 3302

hope this helps cuz thats all i got! lol

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3 years ago
Indicate whether the statement is true of false.
yawa3891 [41]

The statement is false, as the system can have no solutions or infinite solutions.

<h3>Is the statement true or false?</h3>

The statement says that a system of linear equations with 3 variables and 3 equations has one solution.

If the variables are x, y, and z, then the system can be written as:

a_1*x + b_1*y + c_1*z = d_1\\\\a_2*x + b_2*y + c_2*z = d_2\\\\a_3*x + b_3*y + c_3*z = d_3

Now, the statement is clearly false. Suppose that we have:

a_1 = a_2 = a_3\\b_1 = b_2 = b_3\\c_1 = c_2 = c_3\\\\d_1 \neq d_2 \neq  d_3

Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.

Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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Step-by-step explanation:

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Step-by-step explanation:

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