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Kay [80]
3 years ago
10

Why is the numerator the only number that changes when using fractions​

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
It will always depend on the problem. If the denominator isn't the same as the first fraction, then their will be a different number. But if its the same, than the numerator is the only part that will change because it adds on unto it. :)
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6 = -4 + X<br><br><br> Random Question: What's your favorite subject
Inga [223]

Answer:

x=10             US HISTORY :)

Step-by-step explanation:

6=-4 +X

+4  +4

X=10

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8 0
4 years ago
Nineteen less than 6 times a number is the same as 16 more than the number. The equation is The solution is x -7 7.​
Crank

Answer:

The number is 7

Step-by-step explanation:

let the said number be x

Nineteeen less than 6 times a number;

6x - 19

equals; 16 more than the number; this is 16 + x

Thus;

6x - 19 = 16 + x

6x-x = 16 + 19

5x = 35

x = 35/5

x = 7

3 0
3 years ago
I need help with this iready question!
Ivan

Answer:

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4 0
4 years ago
Last homework for mathematics, mr Thompson!
Flura [38]

Answers:

  1. Have a common difference
  2. Have a common factor
  3. Have a linear first difference

============================================================

Explanation:

Linear functions, such as y = 2x+5, have a common difference. In that example, the common difference would be 2 since we add 2 to each term to get the next one. Consider when x = 1 and that leads to y = 7. Then when x = 2, we have y = 9. Then when x = 3, we have y = 11, and so on. The sequence of y values {7,9,11,...} shows we add 2 each time.

------------------

Exponential functions have us multiply the previous term by some common factor to get the next term. A sequence like {2,6,18,...} has us multiply by 3 each time and the exponential function modeling this sequence is y = 2(3)^(x-1) where x is a natural number. So this is an example showing that exponential functions have a common factor, or we can call this a common ratio.

------------------

Quadratic functions are a bit strange.

Let's consider the quadratic of y = x^2. The sequence of y values it generates is {1,4,9,16,25...} for positive integers x = 1, 2, 3, 4, 5....

Let's subtract the adjacent terms (larger - smaller)

  • 4-1 = 3
  • 9-4 = 5
  • 16-9 = 7
  • 25-16 = 9

Note the results of 3,5,7,9 are in a linear sequence (we're adding 2 to each increment value, so the next increment would be +11). We can consider this a linear first difference.

------------------

For any of these functions, I'm restricting x to be an integer and x = 1 is the smallest input possible.

6 0
3 years ago
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