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Setler79 [48]
3 years ago
13

Nineteen less than 6 times a number is the same as 16 more than the number. The equation is The solution is x -7 7.​

Mathematics
1 answer:
Crank3 years ago
3 0

Answer:

The number is 7

Step-by-step explanation:

let the said number be x

Nineteeen less than 6 times a number;

6x - 19

equals; 16 more than the number; this is 16 + x

Thus;

6x - 19 = 16 + x

6x-x = 16 + 19

5x = 35

x = 35/5

x = 7

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Answer:

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Step-by-step explanation:

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The car requires c gallons for 448 miles

c = 448 × 1 / 32

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3 0
3 years ago
What is the answer to this?
Keith_Richards [23]

Answer:

Y = 28.31

Z = 13.29

Angle A = 28

Step-by-step explanation:

For Angle A:

Remember a triangle has a total of 180 degree angles. So set up your formula as

180 - 62 -90 = Angle A

For Y:

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.  

sin (B) = opp/hyp or b/c or (y)

sinB = 62

b = 25

Rewrite as c=b/2SinB -> c=25/sin62 -> Y = 28.31

For Z:

Use the Pythagorean theorem to find the unknown side.

z^{2}  = 28.31^{2}  - 25^{2}

z = 13.29

3 0
3 years ago
Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. Include all
jeka94

ANSWER

y-1= \frac{1}{3} (x- 6)

EXPLANATION

We want to write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3.

The slope of this line is negative reciprocal of -3.

m =  -  \frac{1}{ - 3}  =  \frac{1}{3}

The point-slope form is given by:

y-y_1=m(x-x_1)

We substitute the point and the slope to get;

y-1= \frac{1}{3} (x- 6)

4 0
3 years ago
Read 2 more answers
The force f acting on a charged object varies inversely to the square of its distance r from another charged object. When 2 obje
o-na [289]

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Step-by-step explanation: )

7 0
3 years ago
Use the figure to write the segment addition postulate, write an equation and solve for x.
Alenkinab [10]

Answer:

5. x = -1

6. x = 2

Step-by-step explanation:

5. AB = 5

BC = 2x + 6

AC = x + 10

AB + BC = AC (segment addition postulate)

5 + 2x + 6 = x + 10 (substitution)

Collect like terms

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2x - x = - 11 + 10

x = -1

6. AB = 9x + 7

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AC = 39

AB + BC = AC (segment addition postulate)

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Solve for x

9x + 7 - 3x + 20 = 39

Collect like terms

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Subtract 27 from both sides

6x + 27 - 27 = 39 - 27

6x = 12

Divided both sides by 6

6x/6 = 12/6

x = 2

4 0
3 years ago
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