Nineteen less than 6 times a number is the same as 16 more than the number. The equation is The solution is x -7 7.
1 answer:
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Given:
The data values are:
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
To find:
The outliers of the given data set.
Solution:
We have,
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
Divide the data set in two equal parts.
(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)
Divide each parenthesis in two equal parts.
(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)
Now,
And
The interquartile range is:
The data values lies outside the interval are known as outliers.
All the data values lie in the interval [6,22]. So, there are no outliers.
Hence, the correct option is 4.
First, let's use the given information to determine the function's amplitude, midline, and period.
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
= Solution
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
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