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Rom4ik [11]
3 years ago
15

100 POINTS FOR WHOEVER ANSWER THIS QUESTION FULLY!!!

Mathematics
1 answer:
natulia [17]3 years ago
7 0

Answer:

  • Yes, diagonals bisect each other

Step-by-step explanation:

<em>See attached</em>

Plot the points on the coordinate plane

Visually, it is seen that the diagonals bisect each other.

We can prove this by calculating midpoints of AC and BD

<u>Midpoint of AC has coordinates of:</u>

  • x = (1 - 1)/2 = 0
  • y = (4 - 4)/2 = 0

<u>Midpoint of BD has coordinates of:</u>

  • x = (4 - 4)/2 = 0
  • y = (-1 + 1)/2 = 0

As per calculations the origin is the bisector of the diagonals.

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Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot? x (RootIndex 3 StartRoot 6 x EndRoot) 6 (
aliya0001 [1]

Answer:

4 (RootIndex 3 StartRoot 6 x squared EndRoot)  = 4\sqrt[3]{6x^2}

Step-by-step explanation:

  • <em>Added radical forms to the question for better visibility.</em>

Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot = \sqrt[3]{6x^2} ?

  1. x (RootIndex 3 StartRoot 6 x EndRoot) =  x\sqrt[3]{6x}
  2. 6 (RootIndex 3 StartRoot x squared EndRoot)  = 6\sqrt[3]{x^2}
  3. 4 (RootIndex 3 StartRoot 6 x squared EndRoot)  = 4\sqrt[3]{6x^2}
  4. x (RootIndex 3 StartRoot 6 EndRoot) = x\sqrt[3]{6}
<h3>Solution</h3>
  • <em>Like radicals are radicals that have the same root number and expression under the root.</em>

1)  x\sqrt[3]{6x} = \sqrt[3]{6x^4}

  • No, incorrect

2) 6\sqrt[3]{x^2} = \sqrt[3]{6^3x}

  • No, incorrect

3) 4\sqrt[3]{6x^2}

  • Yes, correct

4) x\sqrt[3]{6} = \sqrt[3]{6x^3}

  • No, incorrect

Compared with the given radical, we can see from the given choices only 3rd choice is like radical with \sqrt[3]{6x^2}

3 0
3 years ago
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