Let the number of raspberry bushes in one garden = x
And the number of raspberry bushes in second garden = y
Garden one has 5 times as many raspberry bushes as second garden,
So the equation will be,
x = 5y -------(1)
If 22 bushes were transplanted from garden one to the second, number of bushes in both the garden becomes same,
Therefore, (x - 22) = (y + 22)
x - y = 22 + 22
x - y = 44 ------(2)
Substitute the value of x from equation (1) to equation (2)
5y - y = 44
4y = 44
y = 11
Substitute the value of 'y' in equation (1),
x = 5(11)
x = 55
Therefore, Number of bushes in garden one were 55 and in second garden 11 originally.
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Answer:
c. 55.4 ft/s
Step-by-step explanation:
Speed of the object is represented by the function:
where x represents the number of feet the object has fallen. We have to find the speed of the object after it has fallen 48 feet. This means we have to find f(x) for x = 48. Substituting x = 48 in above equation we get:
Thus, rounded to nearest tenth, the speed of the object after it has fallen 48 feet would be 55.4 ft/s
X-y=1
x+y=3
You see the y's can cancel out. So add it together and you have:
2x=4
x=2
Now that you have x, plug it in to one of the equations to find y.
I will plug it into the first one.
(2)-y=1
-y=-1
y=1
