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pickupchik [31]
3 years ago
12

Deanna has 80 books in her collection. If 60% of the books are fiction, how many of the books are nonfiction?

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0

if 60% is fiction, then 40% are non fiction

80 x 40% =

80 x 0.40 = 32

 32 books are nonfiction

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Step-by-step explanation:

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3 years ago
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Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
4 years ago
a spinner has 6 equal-sized sections numbered 1,1,2,2,3and 4. what is the sample space for the spinner, and what is the probabil
Nezavi [6.7K]

Answer:

S={1, 1, 2, 2, 3, 4}

Probability of spinning a 1 = 1 in 3 or 33%

Step-by-step explanation:

The sample space is the set of all possible outcomes in an experiment. The outcomes here are the numbers in each section of the spinner: 1, 1, 2, 2, 3, 4. The sample space is:

S={1, 1, 2, 2, 3, 4}

Two out of six possible outcomes are "1s", therefore the probability of spinnin a 1 is:

P(1)=\frac{2}{6}=\frac{1}{3}=33.33\%

The probability of spinning a 1 is 1 in 3 or 33%.

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4 years ago
What are the critical points of an ellipse??
strojnjashka [21]
Idk sorry but i have not learned this yet sorry 
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