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3 years ago

Given the following functions f(x) and g(x), solve

Mathematics

1 answer:

Blizzard [7]3 years ago

6 0

Answer:

-5

Step-by-step explanation:

Given the functions

f(x) = 2x - 20

g(x) = x - 1

f(x)/g(x) = 2x - 20/x-1

f/g(x) = 2x - 20/x-1

Substituting x = -5 int the result

f/g(5) = 2(5) - 20/5-1

f/g(5) = 10 - 20/4

f/g(5) = -10/4

f/g(5) = -5

Hence the result is -5

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Help plz test !! Four more than the product of a number and 10 is at most the opposite of 12.

professor190 [17]

Answer:

-1.6

Step-by-step explanation:

4 + 10x = -12

10x = -12 -4

x= -1.6

5 0

3 years ago

Someone please help with 9th question !!!!

meriva

$LIMITS \: \: AND \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: DERIVATIVES$

Heya !

Check the attachment.
Hope it helps you :)

5 0

3 years ago

If R = 25 cm and S = 7 cm, what is the length of T?

Levart [38]

Answer: 24cm

Step-by-step explanation:

R = 25 cm

S = 7 cm

T = ?

The square of equals to the addition of the square of S and the square of T.

R^2 = S^2 + T^2

25^2 = 7^2 + T^2

T^2 = 25^2 - 7^2

T^2 = 625 - 49

T =✓576

T = 24cm

8 0

3 years ago

Write a function for the situation discribed and find the value after 5 yrs. A $12,500 car depreciates 9% each year. Please help

sweet [91]

$\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &12500\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=12500(1-0.09)^t\implies A=12500(0.91)^t
\\\\\\
\textit{after 5 years t = 5}\qquad A=12500(0.91)^5$

and surely you know how much that is.

5 0

4 years ago

Decide, without calculation, if each of the integrals below are positive, negative, or zero. Let D be the region inside the unit

Schach [20]

The integrals over B and T will be positive. Keeping $y$ fixed, $xe^x$ is strictly increasing over D as $x$ increases, so the integrals over $x$ (i.e. the bottom/top left quadrants of D) is negative but the integrals over $x>0$ are *more* positive.

The integrals over R and L are zero. If we take $f(x,y)=xe^x$ , then $f(x,-y)=f(x,y)$ , which is to say $f$ is symmetric across the $x$ -axis. For the same reason, the integral over all of D is also zero.

4 0

4 years ago