Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm
step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm
step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm
step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm
step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD
step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular
therefore
the shape is a square wit length side √18 cm
area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²
the answer is18 cm²see the attached figure
Answer:
y=-4/13x-28/13
Step-by-step explanation:
m=y2-y1/x2-x1
m=-4-0/6-(-7)
m=-4-0/6+7
m=-4/13
y-y1=m(x-x1)
y-0=-4/13(x-(-7))
y-0=-4/13x-28/13
y=-4/13x-28/13
x^2*(-3x)=-3x^3. The power of x becomes 3 because you add the powers of x. (2+1=3)
Answer:
-1/3
Step-by-step explanation:
if we use the rise over run method we see a fall of 1 and a run of 3. since we are using fall instead of rise that makes this slope negative. hope this helped :)
The answer would be : A parallelogram with congruent sides does NOT guarantee that a quadrilateral is a rectangle