95i is a root of f(x)=x^2 +9025. find the other roots of f(x)

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

5 0

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

${x }^{2} - {95}^{2} {i}^{2} = 0 \\ {x }^{2} + {95}^{2} = 0 \\ {x }^{2} + 9025= 0 \\ f(x) = 0$

this, roots are -95i and 95i

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