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ioda
2 years ago
8

Function Composition: Let the function

3+6x" alt="f(x)= 3+6x" align="absmiddle" class="latex-formula"> , determine:

Mathematics
1 answer:
V125BC [204]2 years ago
4 0

Answer:

<u>Given </u>

  • f(x) = 3 + 6x

A

<u>Find the inverse of f(x):</u>

  • x = 3 + 6f⁻¹(x)
  • 6f⁻¹(x) = x - 3
  • f⁻¹(x) = (x - 3) / 6

B

  • f · f⁻¹( ∛5/6) =
  • f( f⁻¹( ∛5/6)) =
  • f((∛5/6 - 3)/6) =
  • 3 + 6((∛5/6 - 3)/6) =
  • 3 + ∛5/6 - 3 =
  • ∛5/6

C

  • f · f⁻¹(x) =
  • f(f⁻¹(x)) =
  • f((x - 3)/6) =
  • 3 + 6(x - 3)/6 =
  • 3 + x - 3 =
  • x
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Given the figure below, find the values of x and z.
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Answer:

x=9

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Step-by-step explanation:

Angle 107 and 8x+35 are vertical angles, so they are equal

107 = 8x+35

Subtract 35 from each side

107-35 = 8x+35

72 = 8x

Divide by 8

72/8 = 8x/8

9 =x

We also know that 107 and z are supplementary angles since they form a straight line.  This means they add to 180 degrees

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gizmo_the_mogwai [7]
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An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
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area of the base=b²
perimeter of the base=4*b

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substitute equation 1 in equation 2
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the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
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3 years ago
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