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sladkih [1.3K]
3 years ago
7

Please help me with the answer to these. The second picture goes along with the first

Mathematics
1 answer:
deff fn [24]3 years ago
8 0
39 cents that would be the answer for your question hopefully
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Caden is a bird enthusiast and is trying to estimate the number of hawks living in his region. He traps 23 hawks and tags them.
serious [3.7K]
I believe the answer is 415
PLEASE MARK BRAINIEST!
6 0
3 years ago
The length of a rectangle is increasing at a rate of and its width is increasing at a rate of . when the length is 20 cm and the
pav-90 [236]

<span><span>220<span> cm2</span>/s </span>
 EXPLINATION</span>

L length of rectangel (cm)

W width of rectangel(cm)

A area of rectangel (cm²)

T time (s)

we are told that:

d1\dt=8cm\s(const),and dw\dt =3cm\s(const)

the area of the rectangel is

A=LW

Differentiating wrt t (using the product rule) we get;

<span><span><span>dA</span><span>dt</span></span>=<span>(l)</span><span>(<span><span>dw</span><span>dt</span></span>)</span>+<span>(<span><span>dl</span><span>dt</span></span>)</span><span>(w)</span></span>

∴<span><span>dA</span><span>dt</span></span>=3l+8w

So when <span>l=20</span><span> and </span><span>w=10⇒</span>
<span>     <span><span>dA</span><span>dt</span></span>=3⋅20+8⋅20</span>
<span>∴<span><span>dA</span><span>dt</span></span>=60+160</span>
<span>∴<span><span>dA</span><span>dt</span></span>=220<span> cm2</span>/<span>s</span></span>

8 0
3 years ago
-5x+19y=-11<br> Solve for y
valina [46]
-11=-5x+19y
5x-11=19y
(5x-11)/19=y
7 0
3 years ago
Read 2 more answers
HELP ME ASAP!!!
nadezda [96]

Answer:

1 \frac{7}{12}

3 \frac{19}{24}

8 \frac{3}{10}

5 \frac{1}{7}

5 \frac{5}{12}

3 \frac{11}{15}

Step-by-step explanation:

To add or subtract you need to make the denominator the same. To do this you need to find the least common multiple.

7 0
3 years ago
Read 2 more answers
A taxi company charges an initial fee of $2.50 plus $2.50 per mile , write an equation in two variables
Assoli18 [71]

Cost(x) = $2.50 + ($250/mi)x

7 0
4 years ago
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