3 years ago

Please help me with the answer to these. The second picture goes along with the first

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

39 cents that would be the answer for your question hopefully

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(a^3)^6 = (a^2)^x what is x?

alexgriva [62]

Answer:

Step-by-step explanation:

Solution

Here,

(a^3)^6=(a^2)^x

or, a^18=a^2x

or, 18=2x

or, x=18/2

x=9

8 0

3 years ago

Point B is on line segment AC. If AB = x + 6, BC = x + 8 and AC = 10, then find the value of x.

kumpel [21]

Step-by-step explanation:

this simply means that the sum of both short segments must be the same as the length of the whole line.

so,

x + 6 + x + 8 = 10

2x + 14 = 10

x + 7 = 5

x = 5 - 7 = -2

7 0

2 years ago

Simplify 15 to the 18th power over 15 to the 3rd power. <br> 15^6<br> 15^15 <br> 1^6<br> 1^15

KIM [24]

Well the simplest power of 15^8 is 3^15 and the simplest form if 15^3 is 15^15

8 0

2 years ago

M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)

Deffense [45]

Answer:

Part 1) $MD=9\ units$

Part 2) $DC=12\ units$

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

In this problem

$MD=ME=MF$ ------> is the radius of a circle inscribed inside the triangle

we have that

$MF=9\ units$

therefore

$ME=9\ units$

$MD=9\ units$

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

$MC^{2} =MD^{2}+DC^{2}$

we have

$MD=9\ units$

$MC=15\ units$

substitute

$15^{2} =9^{2}+DC^{2}$

$DC^{2}=225-81$

$DC=\sqrt{144}\ units$

$DC=12\ units$

6 0

3 years ago

There are 9 socks in a bag. 1 of those socks is blue.

inessss [21]

1/9 or 11/100

Hope that helps

4 0

3 years ago