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vovangra [49]
3 years ago
13

The least common multiple of two numbers is 60, and one of the numbers is 7 less than the other number. What are the numbers? Ex

plain your answer.
Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

Two numbers (integer only): 5 , 12

Step-by-step explanation:

Suppose two numbers are integers: ax and ay, a is common factor and x,y no more common factor

axy = 60   a: 1,2,3,4,6,10,12,30

ax - ay = a(x-y) = 7

after test , I exclude 3,4,6,10,12,30

if a=1    xy=60    (x,y): (3,10) (4,15) (5,12)

(5,12): LCM: 5*12=60     12-5=7

if a=2       xy=30  (x,y): (2,15) (3,10) (5,6)  No solution in this combination

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Answer:

k = - 2

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Lines g(x) and f(x) passes through the points (2, 0), (0, 2) & (4, 0), (0, 4)

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Find the value or x that makes CDE FGH very confused
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Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.
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For this case we must solve the following equation:

\sqrt {4x ^ 2} - \sqrt {x ^ 2} = 6

To solve we follow the steps below:

We square both sides of the equation squared:

(\sqrt {4x ^ 2} - \sqrt {x ^ 2}) ^ 2 = 6 ^ 2\\(\sqrt {4x ^ 2}) ^ 2-2 (\sqrt {4x ^ 2}) (\sqrt {x ^ 2}) + (\sqrt {x ^ 2}) ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 2 * x ^ 2}) + x ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 4}) + x ^ 2 = 36\\4x ^ 2-2 (2x ^ 2) + x ^ 2 = 36\\4x ^ 2-4x ^ 2 + x ^ 2 = 36\\x ^ 2 = 36\\x = \pm \sqrt {36}\\x = \pm6

We choose the positive value because we talk about $. x = 6

Answer:

$6

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