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Leni [432]
3 years ago
7

(a + 3)(a - 2) please help

Mathematics
1 answer:
gregori [183]3 years ago
3 0
Final Answer: a2+a−6
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3(-4y+5)-8(-2y-4) can be written in the form (ay+b) by following the following steps:
Dominik [7]

Answer:

Does the correct answer necessarily HAVE to be one of those three options? Because I'm looking at the steps and there seems to no mistakes at all. Forgive me if I'm mistaken though!

Step-by-step explanation:

4 0
3 years ago
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If X=2 Y=3 then, xy^2
Agata [3.3K]

Answer:

18

Step-by-step explanation:

2 x 3^2

2 x 9

18

3 0
4 years ago
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Mohamed and Li Jing were asked to find an explicit formula for the sequence -5, -25, -125, -625,....
Nuetrik [128]

Answer:

Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

Step-by-step explanation:

Considering the sequence

-5,\:-25,\:-125,\:-625,...

A geometric sequence has a constant ratio r and is defined by

g_n=g_0\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{g_{n+1}}{g_n}

\frac{-25}{-5}=5,\:\quad \frac{-125}{-25}=5,\:\quad \frac{-625}{-125}=5

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=5

So, the sequence is geometric.

as

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

g_1=-5

r=5

so

g_n=g_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

g_n=-5\cdot \:5^{n-1}

Therefore, Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

8 0
4 years ago
There goes my hopes for Virtuoso rank....
Tpy6a [65]
Y = x^2 + 10x - 171
y = (x - 9)(x + 19)

x - 9= 0 x + 19 = 0
x = 9 x = -19

Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9
3 0
3 years ago
Which is equivalent to
Kitty [74]

Answer:

2^2 your welcome

Step-by-step explanation:

8 0
3 years ago
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