All categories

3 years ago

(a + 3)(a - 2) please help

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Final Answer: a2+a−6

You might be interested in

3(-4y+5)-8(-2y-4) can be written in the form (ay+b) by following the following steps:

Dominik [7]

Answer:

Does the correct answer necessarily HAVE to be one of those three options? Because I'm looking at the steps and there seems to no mistakes at all. Forgive me if I'm mistaken though!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If X=2 Y=3 then, xy^2

Agata [3.3K]

Answer:

Step-by-step explanation:

2 x 3^2

2 x 9

3 0

4 years ago

Read 2 more answers

Mohamed and Li Jing were asked to find an explicit formula for the sequence -5, -25, -125, -625,....

Nuetrik [128]

Answer:

Li Jing's formula i.e. $\boxed{g_n=-5\cdot \:5^{n-1}}$ is right.

Step-by-step explanation:

Considering the sequence

$-5,\:-25,\:-125,\:-625,...$

A geometric sequence has a constant ratio r and is defined by

$g_n=g_0\cdot r^{n-1}$

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{g_{n+1}}{g_n}$

$\frac{-25}{-5}=5,\:\quad \frac{-125}{-25}=5,\:\quad \frac{-625}{-125}=5$

$\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$r=5$

So, the sequence is geometric.

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$g_1=-5$

$r=5$

$g_n=g_1\cdot r^{n-1}$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$g_n=-5\cdot \:5^{n-1}$

Therefore, Li Jing's formula i.e. $\boxed{g_n=-5\cdot \:5^{n-1}}$ is right.

8 0

4 years ago

There goes my hopes for Virtuoso rank....

Tpy6a [65]

Y = x^2 + 10x - 171
y = (x - 9)(x + 19)

x - 9= 0 x + 19 = 0
x = 9 x = -19

Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9

3 0

3 years ago

Which is equivalent to

Kitty [74]

Answer:

2^2 your welcome

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers