Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
add 14+8 first, which is 22
then, multiply 6 by 22, which is 132
and lastly, add 12
the answer is 144
Answer:
B
Step-by-step explanation:
5(2x+4)=30
10x+20=30
10x=10
x=1
Answer:
No.
Step-by-Step Explanation:
When two lines are parallel, they might or might not be equal. It is not necessary that they should be equal.
See the triangle below in which two lines are parallel to each other.
Number of plants planted = 23
with a distance of = 3 m
total distance between the first and the last plant = 22x3 ( because starting from first plant we will not take 23)
ans. = 66m
