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Oduvanchick [21]
3 years ago
12

PLS HELP Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement

by measuring the.​

Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

you are already right d

Explanation:

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Predict the molecular geometry about S in the molecule SO2
Inga [223]

Hey there!:


SO2 a Bent molecular shape. The lone pair of electrons is at the top of the SO2 molecule. The SO2 bond angle will be 120 degrees since it has a Bent molecular geometry.


Hope that helps!

5 0
4 years ago
Read 2 more answers
A cough syrup contains 5.0% ethyl alcohol, c2h5oh, by mass. if the density of the solution is 0.9928 g/ml, determine the molarit
WARRIOR [948]
To answer the question above, let us a basis of the 1000 mL or 1 L. 
                 volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%. 
               mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol). 
                       n = 49.64 g/ (46 g/mol) = 1.08 mol
Then, divide the number of moles by the volume (our basis is 1 L)
                       molarity = 1.08 mol/ 1 L = 1.08 M
5 0
3 years ago
4. How many joules of heat are absorbed to raise
hodyreva [135]

. How many joules of heat are absorbed to raise

the temperature of 37 grams of water from 25°C

to 75°C?

7 0
2 years ago
Please help asap! Giving brainliest to correct answer.
Leya [2.2K]

Answer:

C. It may act as an insulator or a conductor.

Explanation:

Group B are the metalloids, so they have properties of both metals and nonmetals.

6 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
3 years ago
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