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yulyashka [42]
3 years ago
11

Except for elements 1 and 2, all other elements are stable with how many electrons in their outermost (valence) energy level? ex

cept for elements 1 and 2, all other elements are stable with how many electrons in their outermost (valence) energy level? 2 8 18 32
Chemistry
2 answers:
Elodia [21]3 years ago
6 0
<span>Having 8 electrons in their outermost level of energy, all these elements are stable. The number of electrons in the outermost level is simply called as valance. These are the electrons in the atom that interact and form the chemical bonds. The stability of the element is also determined by the valance.</span>
Artyom0805 [142]3 years ago
4 0
Answer is: <span>other elements are stable with 8 electrons.
For example sodium has eleven electrons and lost one electron to obtain electron configuration of noble gas neon. </span>₁₁Na⁺ 1s²2s²2p⁶.
Chlorine has 17 electrons (seven valence electrons), chlorine gain one electron to obtain electron configuration of noble gas argon. ₁₇Cl⁻ 1s²2s²2p⁶3s²3p⁶.
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20 c. = 293.15 k.

293.15 - 283.15 = 10

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A binding protein binds to a ligand l with a kd of 400 nm. what is the concentration of ligand when y is (a) 0.25, (b) 0.6, (c)
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The fractional saturation y is defined as :

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Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other product
Greeley [361]

Answer:

a) N2 is the limiting reactant

b) <u>1215.9 grams NH3</u>

<u>c) 2283.6 grams H2</u>

Explanation:

Step 1: Data given

Mass of N2 = 1000 grams

Molar mass N2 = 28 g/mol

Mass of H2 = 2500 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) +3H2(g) → 2NH3(g)

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 1000 grams / 28.0 g/mol

Moles N2 = 35.7 moles

Step 4: Calculate moles H2

Moles H2 = 2500 grams / 2.02 g/mol

Moles H2 = 1237.6 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

<u>N2 is the limiting reactant</u>. There will be consumed 35.7 moles.

H2 is in excess. There will react 3*35.7 = 107.1 moles

There will remain 1237.6 - 107.1= 1130.5 moles H2

This is 1130.5 * 2.2 = <u>2283.6 grams H2</u>

Step 6: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For  35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 71.4 moles * 17.03 g/mol

Mass NH3 = <u>1215.9 grams NH3</u>

7 0
3 years ago
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