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mr_godi [17]
4 years ago
14

In going across a row of the periodic table, protons and electrons are added and ionization energy generally increases. In going

down a column of the periodic table, protons and electrons are also being added but ionization generally decreases. Explain.
Chemistry
1 answer:
RoseWind [281]4 years ago
4 0

Answer:

Explanation:

Ionization energy:

It is the minimum amount of energy required to remove the electron from isolated gaseous atom to make the ion.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell.

When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.  Where as,

When we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

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ethyl chloride, c2h5cl, is used as a local anesthetic. it works by cooling tissue as it vaporizes; its heat of vaporization is 2
Inessa [10]

The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.

<h3>How do we calculate required heat?</h3>

Required amount of heat which can be removed for the vaporization will be calculated as:

Q = (n)(ΔHv), where

  • n = moles of ethyl chloride
  • ΔHv = heat of vaporization = 26.4 kj/mol

Moles will be calculated as:

n = W/M, where

  • W = given mass of ethyl chloride = 20g
  • M = molar mass of ethyl chloride = 64.51 g/mol

n = 20 / 64.51 = 0.31 mol

On putting all these values in the above equation, we get

Q = (0.31)(26.4) = 8.184 kJ

Hence involved amount of heat is 8.184 kJ.

To know more about heat of vaporization, visit the below link:

brainly.com/question/13106213

#SPJ4

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Please help with word equations?
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A solid piece of aluminum (51.0 g) was added to a solution of sodium hydroxide (84.1 g) in water, A balanced equation for this r
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<span>2 NaOH(aq)+ 2 Al(s)+ 2 H</span>₂<span>O → 2 NaAlO</span>₂<span>(aq)+ 3 H</span>₂<span>(g)
</span>  2mol      :     2mol           :                                  3mol
2,14mol   :     1,89mol      :                                  2,835mol
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2,14-1,89=0,25mol


A) Al

B)  

M_{NaOH}=39,4\frac{g}{mol}\\&#10;n=0,25mol \Rightarrow \ \ \ m=n*M_{NaOH}=0,25mol*39,4\frac{g}{mol}=9,85g

C)
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7 0
3 years ago
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