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3 years ago

9

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1 answer:

MAXImum [283]3 years ago

8 0

I believe it is C but i can’t be sure but I hope u get it right!

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how much interest does $1,000 earn at an interest rate of 6% compounded semi annually? what is the balance after 2 years

Contact [7]

Answer:

Interest = A - P = 1015 - 1000 = $15

Step-by-step explanation:

3 0

3 years ago

Someone plzzzz help meee!!!!

Oxana [17]

Find the tangent of the angle, using the height (472) minus the elevated height of the camera (2) which would be 470 meters, and also the distance away from the shuttle, which would be 750. Opposite divided by adjacent would make the tangent 0.626...so using a triangle chart, the closest whole numbered angle 0.626 would be to is 32 degrees.

4 0

3 years ago

9) Which two ratios form a proportion? A) 5 6 and 4 5 B) 6 5 and 4 5 C) 12 15 and 5 4 D) 15 12 and 5 4

Sveta_85 [38]

Answer:

D) 15/12 and 5/4

Step-by-step explanation:

Because when you cross multiply the ratios

15*4 and 12*5

making both ratios a proportion

they both = 60

3 0

3 years ago

Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3

Maru [420]

Answer:

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

Step-by-step explanation:

The geometric progression is:

$9, 3 \sqrt{3}, 3...$

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

$r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}$

That is the common ratio.

Geometric progression is given generally as:

$a_n = ar^{(n - 1)}$

where a = first term

r = common ratio

$a_n$ = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

5 0

3 years ago

Ed Moura has $32000 invested in stocks paying 6% .how much additional money should he invest in certificates of deposit paying 3

inna [77]

Answer:

Ed Moura invest $64000 in certificates of deposit paying 3%

Step-by-step explanation:

Ed Moura has $32000 invested in stocks paying 6%.

Additional money in certificates of deposit paying 3% =x

so that the average return on the two investments is 4%.

32000*6% +3%*x = 4%(32000+x)

32000*0.06 +0.03*x = 0.04(32000+ x)

1920 + 0.03x = 1280 +0 .04x

1920 - 1280 = 0.04x - 0.03x

0.01x = 640

x = 64000

x = $64000

x= $64000 in certificates of deposit paying 3%

Thank you.

4 0

3 years ago