The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
<span>(13a + 5b) + (a + 5b - 3)
</span><span>
= 13a + 5b + a + 5b - 3
= 14a + 10b - 3 </span>
Answer:
no, because it has a constant rate of change
Step-by-step explanation:
this is because the x and y change at the same rate. non linear means that they dont change at the same rate.
Answer:
3rd option
Step-by-step explanation:
(
)(x)
= 
= 
← factorise numerator and denominator
= 
← cancel (2x + 1) on numerator/ denominator
= 
Answer:
Step-by-step explanation:
Let the weight of box Y be w kg.
Box X weighs 33 kg more than Box Y, then the weight of box X is
kg.
Box Z weighs 12 kg more than Box Y, then the weight of box Z is
kg.
The total weight of all boxes is
kg
Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,
or
