Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Answer:
Step-by-step explanation:
Q=+5414x=5
<u>Answer:</u>
Glen uses 15.65 inches fabrics for headbands and 9.68 inches for each player
<u>Explanation:</u>
Given the fabric used are:
For headbands, 641.65 inches for 41 people (39 players and 2 coach)
Therefore, applying the concept of unitary method
41 people = 641.65 inches
1 person = 
= 15.65 inches
For wristbands, 377.52 inches for 39 players
39 players = 377.52 inches
1 player = 
= 9.68 inches
Therefore, Glen uses 15.65 inches fabrics for headbands and 9.68 inches for each player
The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
