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elena55 [62]
3 years ago
8

John left the museum and drove south at a rate of 55 mph. Sally left four hours later driving 10 mph faster than John in an effo

rt to catch up to him. How
long did Sally have to drive to catch up with John?
28 hours
22 hours
20 hours
18 hours
Mathematics
1 answer:
Leona [35]3 years ago
5 0

Answer:

22 hours (B)

Step-by-step explanation:

John's velocity = 55mph

Sally's velocity = 65mph

John's time taken = x

Sally's time taken = x - 4

since they must cover the same distance.

and, distance = vel × time

Sally's vel × time = John's vel × time

55x = 65(x-4)

55x = 65x - 220

-10x = -220

x = 22 hours.

Therefore, Sally catches up after 22 hours

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Answer:

69

Step-by-step explanation:

-y/3 = -23

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=> -y = -69

=> y = 69

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What is the range of h?
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Step-by-step explanation:

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Solve the inequality -8x - 10 &gt; 7x + 20.<br> OX-30<br> Ox&gt;-2<br> Ox&gt;-30<br> 0x&lt;-2
galina1969 [7]

Answer:

<h2>x < - 2</h2>

Step-by-step explanation:

-8x - 10 > 7x + 20

First subtract 7x from both sides of the inequality

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<u>Add 10 to both sides of the inequality</u>

- 15x + 1 0 - 10 > 20 + 10 \\  - 15x > 30

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We have the final answer as

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Hope this helps you

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Kitty [74]

Answer:

Step-by-step explanation:

hello :

5x²+8x-4  quadratic expression when : a = 5  and  b=8  and  c= -4

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us factorisation : a(X-X1)(X-X2)

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you can verify ;  (x+2)(5x-2) = 5x²-2x+10x-4 = 5x²+8x-4

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