<span>I got 18 x 18 = 324.</span>
Volume is 4/3(3.14)(r)^2
the radius is 5.2 ft
Answer:
Step-by-step explanation:
Question says that it uses 120 feet of fencing material to enclose three sides of the play area. This means there are 3 sides. Putting this into equation, we have something like this.
120 = L + 2W
Where
LW = area.
Again, in order to maximize the area with the given fencing, from the equation written above, then Width, w must be = 30 feet and length, l must be = 60
On substituting, we have
A = LW = (120 - 2W) W
From the first equation, making L the subject of the formula, we have this
L = 120 - 2W, which then we substituted above.
On simplification, we have
L = 120W -2W²
Differentiating, we have
A' = 120 - 4W = 0
Remember that W = 30
So therefore, L = 120 - 2(30) = 60 feet
Answer:
below
Step-by-step explanation:
1) slope = rise / run
2 coordinates are (-4, 0), (0, 2).
2 - 0 = 2
0 -- 4 = 4
2 / 4 = 1/2 so the slope is 0.5 or ½
2) it crosses the y axis at the average of the origin and 4.
4 + 0 = 4 / 2 = 2 so y intercept is 2.
3) in y= mx + b form
f(x) = ½x + 2, or, f(x) = 0.5x + 2
