Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound
mixture:
twice as many peanuts as almond; total cost of mixture is 21.
a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a
1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3
almonds = 3 lbs
peanuts = 2a = 2(3) = 6lbs
raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs
<span>My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins </span>
Answer:
The mass is greater by 10.502 grams. If you subtract 27.33 from 16.718, you get 10.502. Therefore, the mass of the second coin is greater than the first coin by 10.502 grams.
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Please try to be more specific. What I think you meant was "what is the area under the standard normal curve to the left of 2.6 standard deviations above the mean?" If that's it, the area can be found from a table of z-scores (look for z=2.6) or by using a calculator:
normalcdf(-100,2.6) = 0.995.
Answer:
No Inez is not correct.
Step-by-step explanation:
(1/3 is greater than 1/5)
