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lana [24]
3 years ago
11

Please help me out thank you!

Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

Step-by-step explanation:

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
What is the answer to this
arlik [135]

S\frac{O}{H} C\frac{A}{H} T\frac{O}{A} or Sin\frac{Opposite}{Hypotenuse}Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}


At the point/angle E:

- the adjacent side(side <u>next to</u> the point/angle) is ED

- the opposite side(side of the triangle <u>across</u> from the point/angle) is DF

- the hypotenuse (the<u> longest side</u> of the triangle) is EF.


sin ∠E = \frac{opposite}{hypotenuse}

sin ∠E = \frac{6}{10} = \frac{3}{5} (simplified)

5 0
4 years ago
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The expression 3^2*3^3*3^4 is equivalent to?<br> Show all your work please
loris [4]
Cool! So OK I'll take you through it.
You just need to take everything 1 step at a time, as you might already know.

First
3 to the second is 9

Second
The first part included like this 9*(3 to the third) which is 243

Third
The second part is included into the question like 243*(3 to the fourth) which is 243*81

Fourth
243*81 = 19,683

Your Answer
(3^2)*(3^3)*3^4) = 19,693

Hope That Helps and Correct Me If I'm Wrong!

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4 years ago
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Give the “best” big-oh notation to describe the complexity of the algorithm that prints all bit strings of length n.
artcher [175]

It is correct to state that a bit can be in one of 2 states, either 1 or 0.

<h3>What is a bit?</h3>

A bit is is a single binary digit. A bit can either be "1" or "0".

<h3>What is the explanation to the above answer?</h3>

We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.

  • The first time, for generation and
  • The second for reading.

Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)

Learn more about bits at;
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#SPJ1

4 0
2 years ago
Quien me ayuda es suma de polinomios
arsen [322]
Sorry no espanol...sorry
6 0
3 years ago
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