You would have to be 30 because multiples of 5 would only be 25 and 30 inbetween those numbers, and 25 is not an even number which it must be if you can say the number counting by 2s
X-1/2=15 1/4
15 1/4 = 15*4 + 1 = 61/4
61/4
x - 1/2 = 61/4
+1/2 +1/2
61/4 + 2/4 = 63/4
x = 63/4
Yes.
For example, the LCM of 12 and 36 is 36, because factoring these numbers gives
12 = 2^2 * 3
36 = 2^2 * 3^2
So, to match them, just multiply the twelve by 3, then they're both 36.
Answer:
Use the app photomath
Step-by-step explanation:
9514 1404 393
Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
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Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
