=> x² = (2.4)² + (4.8)²
=> x² = 5.76 + 23.04
=> x² = 28.8
=> x = 5.366563146
=> x = 5.4
Ans: 2nd option (5.4)
Hope this helps!
Probably the easiest way to do this is to use synthetic division. We already know one of the zeros of the quadratic so we can use that number to find the other zero. If the point is (4, 0), then when y = 0, x = 4. Thus, 4 is a zero. Put 4 outside the "box" and put the coefficients from the quadratic inside, like this: 4 (1 -1 -12). Draw a line and bring down the first one under it. Multiply that 1 by the 4 to get 4. Put that 4 up under the -1 and add to get 3. Multiply 3 by 4 to get 12. Put that 12 up under the -12 and add to get 0. The numbers left under the line are the coefficients for the next polynomial, called the depressed polynomial, and this polyomial is one degree less than the one we started with. Those coefficients are 1 and 3. Therefore, the polynomial is x + 3 = 0. That means that the other zero, or x-intercept, is x = -3.
X = advance
y= same day
x+y=70
30x+15y=1650
--------------------------
30x+15y=1650
- x+y=70 (x15) -> 15x+15y=1050
--------------------------
30x+15y=1650
-15x+15y=1050
--------------------------
15x=600
x=600/15
x=40
so now u can insert the price of x AKA the price of the advanced ticket to find our the price of the same day ticket.
x+y=70
so
40+ y=70
y=70-40
y=30
x = advance =40
y= same day =30
I have encountered this question before. Since only the product of the ages is given, there are a lot of possible combinations.
3 kids, has a youngest child - means that the 3 kids have different ages.
I performed a prime factorization on 72.
72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 3 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible age combination:
1 x 8 x 9 = 72
2 x 4 x 9 = 72
3 x 4 x 6 = 72
1 x 6 x 12 = 72
1 x 4 x 18 = 72
