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solmaris [256]
3 years ago
11

You throw a dart at the board shown. Your dart is

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

dart

Step-by-step explanation:

ur dart is equal ...

no help

i am not good enough to make sure that

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A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
3 years ago
Read 2 more answers
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
4 years ago
Simplify: (∛125 + ∛64 - ∛1)^1/3​
Liono4ka [1.6K]

Answer:

2

Step-by-step explanation:

(∛125 + ∛64 - ∛1)^1/3​

(5 + 4 - 1)^1/3

8^1/3

= 2

8 0
2 years ago
Read 2 more answers
The pie chart shows the information about the favourite ice creme flavour of each student in a schcool.There are 720 students at
Novay_Z [31]

Answer:

there would be many diffrent answers

Step-by-step explanation:

provide the full question, i can deduct that there are many ice cream flavors.

6 0
3 years ago
I am always in shapes and never straight or round. I make sharp turns and will easily be found. A shape is in
Elden [556K]
I think it’s a 2d shape
3 0
3 years ago
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