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Igoryamba
3 years ago
5

Homework please help

Mathematics
2 answers:
irinina [24]3 years ago
5 0
The answer is B because you would multiply 3 with 2 giving you a total of 6 and then you add the 2 and you get 8
Digiron [165]3 years ago
3 0

Answer:

I think B is the right one.

Step-by-step explanation:

Hope this helped

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Which of the following has no solution?
Softa [21]

Answer:

(x + 1 s 1) n (x + 12 1)

(x +1<1) n (x + 1 > 1)

Step-by-step explanation:

Just simplify each the statements.

Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.

(x + 1<-1) n (x + 1< 1)

(x <-2) n (x < 0) which is true, so there is a solution.

(x + 1 s 1) n (x + 12 1)

this doesn't make sense so there is no solution.

(x +1<1) n (x + 1 > 1)

(x < 0) n (x > 0)

This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.

5 0
3 years ago
Answer pls in standard form too
romanna [79]

Answer:

a)

Slope form y=2x+3

Standard form 2x-y=-3

b)

Slope y=3/5x-6

Standard 3x-5y=30

c)

slope y=-3/2x+9

standard 3x+2y=18

d)

slope y=-3x+0

standard = 3x+y=0

Step-by-step explanation:

a)

Slope form y=2x+3

Standard form 2x-y=-3

b)

Slope y=3/5x-6

Standard 3x-5y=30

c)

slope y=-3/2x+9

standard 3x+2y=18

d)

slope y=-3x+0

standard = 3x+y=0

7 0
2 years ago
the table is 19 lb. 4 oz. the chair is 11 lb. 9oz. compare to the table, how much heavier are the two chairs?​
Sever21 [200]

Answer:

3.875 lb

Step-by-step explanation:

Weight of table = 19lb 4 oz = 19-4/16 lb = 19.25 lb

Weight of each chair = 11 lb 9 oz = 11-9/16 lb = 11.5625 lb

Weight of 2 chairs = 2 x 11.5625 = 23.125 lb

Difference in weight between 2 chairs and one table

= 23.125 - 19.25

= 3.875 lb

5 0
3 years ago
The ratio of boys to girls in a class is 7:5. There are 36 students in the class. How many students are girls?
Art [367]

Answer:

15 students are girls

Step-by-step explanation:

7+5=12

36÷12=3

3x5=15

5 0
3 years ago
Read 2 more answers
Use the given information to find the lengths of the other two sides of the right triangle if side a is opposite angle A, side b
weeeeeb [17]

c = \frac{4\sqrt{30} }{9}

using Pythagoras' identity on the right triangle

c = √( 4² + (\frac{28}{9} )² ) = √16 + \frac{2080}{81}

 = \frac{\sqrt{2080} }{9} = \frac{4\sqrt{130} }{9}


4 0
3 years ago
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