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The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
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The graph that shows the solution to the system of inequalities is: C (see the image attached below).
<h3>How to Determine the Graph of the Solution to a System of Inequalities?</h3>Given the following systems of inequalities:
y < -1/3x + 1
y ≤ 2x - 3
Below are the features of the graph that represents a solution to the system of inequalities:
- The boundary line of y < -1/3x + 1 would be a dashed line and the shaded area would be below it, because of the inequality sign, "<".
- The boundary lines of y ≤ 2x - 3 would be a solid line and the shaded area would be below it, because of the inequality sign, "≤".
- The slope of the shaded line that represents y < -1/3x + 1, would be -1/3, and the line would be a decreasing line which intersects the y-axis at 1.
- The slope of the line that represents y ≤ 2x - 3, would be 2, and the line would also be an increasing line that intersects the y-axis at -3.
Therefore, the graph that shows the solution to the system of inequalities is: C (see the image attached below).
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