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Mkey [24]
2 years ago
7

The objective of this task is to use Scapy to estimate the distance, in terms of number of routers, between your VM and a select

ed destination. This is basically what is implemented by the traceroute tool. In this task, we will write our own tool. The idea is quite straightforward: just send a packet (any type) to the destination, with its Time-To-Live (TTL) field set to 1 first. This packet will be dropped by the first router, which will send us an ICMP error message, telling us that the time-to-live has exceeded. That is how we
This project is based on SEED labs by Wenliang Du, Syracuse University.
get the IP address of the first router. We then increase our TTL field to 2, send out another packet, and get the IP address of the second router. We will repeat this procedure until our packet finally reach the destination. It should be noted that this experiment only gets an estimated result, because in theory, not all these packets take the same route (but in practice, they may within a short period of time). The code in the following shows one round in the procedure
a = IP()
a.dst '1.2.3.4
a.ttl = 3
b = ICMP()
send (a/b)
If you are an experienced Python programmer, you can write your tool to perform the entire procedure automatically. If you are new to Python programming, you can do it by manually changing the TTL field in each round, and record the IP address based on your observation from Wireshark. Either way is acceptable, as long as you get the result
Task: Sniffing and-then Spoofing
In this task, you will combine the sniffing and spoofing techniques to implement the following sniff- and-then-spoof program. You need two VMs on the same LAN. From VM A, you ping an IP X. This will generate an ICMP echo request packet. If X is alive, the ping program will receive an echo reply, and print out the response. Your sniff-and-then-spoof program runs on VM B, which monitors the LAN through packet sniffing. Whenever it sees an ICMP echo request, regardless of what the target IP address is, your program should immediately send out an echo reply using the packet spoofing technique. Therefore, regard-less of whether machine X is alive or not, the ping program will always receive a reply, indicating that X is alive. You need to use Scapy to do this task. In your report, you need to provide evidence to demonstrate that your technique works.
Computers and Technology
2 answers:
Stolb23 [73]2 years ago
8 0

Answer:

is this even a legit question

vivado [14]2 years ago
4 0

Answer:

kad ;ikajlfhdakjsfhadskfadhkjfahdjkfadk a jk h

Explanation:

You might be interested in
A data use agreement is required when a researcher uses a limited data set (lds). an lds must have:_________
svetoff [14.1K]

An LDS must have all direct identifiers removed.

According to the HIPPA policy, a Limited Data Set (LDS) is a kind of data set in which direct identifiers are removed.

Limited Data Set  (LDS) is a set of data that can be used for research purposes under the HIPPA policy without any authorization from the patient. However, this kind of data ensures that any kind of identifier information such as the patient's name, relative's name, address, number etc is not shared and not made a part of the research.

Limited Data Set (LDS) shows common information like age, city, and gender information from the data.

The Limited Data Set (LDS) is available to only those researchers with whom the data use agreement has been signed.

To learn more about  Limited Data Set (LDS), click here:

brainly.com/question/2569524

#SPJ4

7 0
1 year ago
Laurence Sims owns a football team that plays its home games in City Stadium. To increase revenue, he is offering a sponsorship
34kurt

Answer:$237,000

Explanation:

7 0
3 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
Electronically, or on paper draw a Binary Search Tree using the values below. Note: Insert each value into the tree in order fro
maria [59]

Answer:

A.)  in order traversal - 9 32 35 14 27 25 2 7 29

B.) pre-order traversal - 25 14 32 9 35 27 7 2 29

C.) post-order traversal - 9 35 32 27 14 2 29 25

Explanation:

Given - 25, 14, 7, 32, 27, 2, 29,9,35

To find - On a separate electronic page or sheet of paper:

1. List the values using in order traversal

2. List the values using pre-order traversal

3. List the values using post-order traversal

Proof -

Given values are -

25, 14, 7, 32, 27, 2, 29,9,35

1.)

In order is -

9 32 35 14 27 25 2 7 29

2.)

Pre-order is - (Root left right)

List nodes of first time visit

25 14 32 9 35 27 7 2 29

3.)

Post-order is - (Left Right Root)

List nodes of third time visit

9 35 32 27 14 2 29 25

5 0
3 years ago
What is the effect of this line of CSS code?
Semenov [28]
The correct answer is C
6 0
2 years ago
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