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Finger [1]
1 year ago
14

Write a program in C++ to Find the Average of the sum of prime numbers between 1 to any given number

Computers and Technology
1 answer:
mixas84 [53]1 year ago
8 0

Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number

<h3>Writting in C++ code:</h3>

<em />

<em>#include <iostream></em>

<em>using namespace std;</em>

<em>bool isPrime(int n){</em>

<em>   for(int i = 2; i < n/2; i++){</em>

<em>      if(n%i == 0){</em>

<em>         return false;</em>

<em>      }</em>

<em>   }</em>

<em>   return true;</em>

<em>}</em>

<em>int findPrimeSum(int n){</em>

<em>   int sumVal = 0;</em>

<em>   for(float i = 2; i <= n; i++){</em>

<em>      if(isPrime(i))</em>

<em>         sumVal += i;</em>

<em>   }</em>

<em>   return sumVal;</em>

<em>}</em>

<em>int main(){</em>

<em>   int n = 15;</em>

<em>   cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>

<em>   return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

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A computer system has a 32KB, 8-way set associative cache, and the block size is 8 bytes. The machine is byte addressable, and p
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Answer:

Offset bits: 3-bits

Set number of cache: 12-bits

Tag bits: 7-bits

22-bit physical address

Explanation:

Since the system is 32K so,

=2⁵.2¹⁰

=2¹⁵

As we know that it is 8-way set associative so,

=2¹⁵/2³

=2¹⁵⁻³

=2¹²

2¹² are cache blocks

22-bit physical address

Off-set bits are 3 as they are calulated from 8-way set associative information.

Set number of cache : 12-bits

For tag-bits:

Add off-set bits and cache bits and subtract from the total bits of physical address.

=22 - (12+3)

=22 - 15

=7

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Answer:

lst = [11, 603, 99, 7, 582, 1];

print("The index of the middle element: " + str(int(len(lst)/2)))

print("The middle element: " + str(lst[int(len(lst)/2)]))

lst.sort()

sorted_lst = lst.reverse()

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lst.append(first_number)

print("New lst: "+ str(lst))

Explanation:

- Initialize a list

- Find the middle index, int(len(lst)/2)

- Find the middle element, lst[int(len(lst)/2)]

- Sort the list in descending order (First sort the list in ascending order than reverse it)

- Get the first element using <em>pop</em> method, and append it to the end using <em>append</em> method

- - - - -

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