Hello from MrBillDoesMath!
Answer: 6 * p^(3/2) * q^4
Discussion:
We are evaluating
sqrt { 36 * p^3 q^8 }
where "sqrt" indicates the square root and the ^ (as in q^8) means "raised to the power of:
The square root of the product is the product of the square roots. (Say that 5 time out loud quickly!). So the above equation becomes
sqrt { 36 * p^3 q^8 } =
sqrt( 36) * sqrt( p^3) * sqrt (q^8)
The square root of 36 is 6 as 6* 6 = 36 so the equation equals
6 * p ^ (3/2) * q^ (8/2)
Note that the square root of a number, for example, r, is the same as raising the number to the (1/2) power. That's where the (1/2) terms came from above.
But 8/2 = 4 so the equation simplifies to
6 * p^(3/2) * q^4
Thank you,
MrB
Umm i think it would be 7 because 7 times 3 is 21
Answer:
972pi in ^3
Step-by-step explanation:
We need to find the volume of the sphere
V = 4/3 pi r^3
The diameter is 18
r = d/2 = 18/2 = 9
V = 4/3 pi ( 9)^3
V = 972pi in ^3
Just plus in x for -3
f(x) = 4(-3)^2 + 3(-3) - 11
f (x) = 4(9) -9 - 11
f(x) = 36 - 20
f(x) = 16
The highest common factor is 7:
49=7*7
84=7*12
91=7*13