Answer:
D
Step-by-step explanation:
diameter of 1 circle = 21.3/3= 7.1
radius of 1 circle= 7.1/3=3.55
area of 1 circle =πr^2=3.14× (3.55)^2=39.57
area of 3 circle= 39.57×3=118.72
therefore,area of shaded portion= area of 3 circle =118.72
<u>The function that represents the </u><u>volume</u><u> of the chest is </u><u>40.</u>
What is a volume simple definition?
- The amount of space occupied by a three-dimensional figure as measured in cubic units (as inches, quarts, or centimeters) cubic capacity.
- The amount of a substance occupying a particular volume.
When the Area of rectangular chest:
A(x) = 20√x /3
⇒ Volume of chest = Base area x Height
Therefore:
(X + 6) × 20√x /3
(20x√x /3 ) + (20 × 6√x/3)
(20x√x /3 ) + (20 × 2 × 3√x/3)
(20x√x/3) + 40√x
Therefore, the correct answer for the drop-down menu is that the first blank is multiply and the second blank is 40.
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Answer:2
Step-by-step explanation:
2.5(2)
=5
Answer:
h(x) * s(x) = 200(1.05)^(x - 1)
Step-by-step explanation:
Our interest equation is s(x) = (1.05)^(x - 1). This is actually a part of a bigger formula for calculating the amount of money accumulated including interest:
A = P(1 + r)^n, where A is the total, P is the principal amount (initial amount), r is the interest rate, and n is the time
Here, we technically already have the (1 + r)^n part; it's just (1.05)^(x - 1). The principle, though, will actually be the 200 because she starts out at $200.
Thus, to combine these, we simply multiply them together to get:
h(x) * s(x) = 200(1.05)^(x - 1)
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,