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bezimeni [28]
3 years ago
8

A submarine starts at sea level and sinks ⅕ mile. An hour later, it rises ⅕ mile. What is the depth, in miles, of the submarine

after the hour
Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Answer:5/-24

Submarine's depth after first minute will be -\frac{5}{24}

Step-by-step explanation:

Submarine is descending at a constant rate = -\frac{5}{6} miles in 4 minutes

Therefore, after the first minute submarine's depth relative to the sea level will be

= \frac{\text{Rate at which submarine is descending}}{\text{Time taken}}

= -\frac{5}{6\times 4}

= -\frac{5}{24}

Therefore, submarine's depth after first minute will be -\frac{5}{24}

not my answer but hope it helps.

Blizzard [7]3 years ago
4 0

Answer:

it takes a yard away from the answer so find out the yard in distance

Step-by-step explanation:

minus 1

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Answer:

Step-by-step explanation:

Given that,

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Then,

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Therefore, 4 brand = 60,000 × 4

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3 years ago
What are the intercepts of 3x – 2y = 12. put answers in as an orders pair<br> (PLEASE HELP)
slega [8]

Answer:

x int (4,0)

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Step-by-step explanation:

4 0
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Llana [10]

Answer:

y = 9/2x -6.5

Step-by-step explanation:

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5 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
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sladkih [1.3K]

Answer:

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                        2        x       18

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Step-by-step explanation:

6 0
3 years ago
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