The probability of the couple having four unaffected and one affected child if both parents are carriers will be A. 0.40.
<h3>How to calculate the probability?</h3>
The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
Unaffected = ¾; affected = ¼
The probability of this couple having four unaffected (either HbAHbA or HbAHbS ) and one affected = n!/a!b! (s^a) (t^b)
n= Total no. of progeny = 5
a = No. of unaffected = 4
b = No. of affected = 1
s = probability of unaffected = 3/4
t = probability of affected = 1/4
Therefore, the probability of the couple having four unaffected and one affected child if both parents are carriers will be:.
= 5! / 4!1! (3/4^4) (1/4^1)
= 120/24 (0.32) (0.25)
= 0.4 = 40%
Therefore, the probability is 0.4.
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A man and woman have five children. What is the probability of this couple having four unaffected (either HbAHbA or HbAHbS ) and one affected child if both parents are carriers?
a. 0.40
b. 0.25
c. 0.08
d. 0.66
