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cluponka [151]
2 years ago
11

Nadia compares the weights, in grams, of some apples and oranges she find the median abs interquartile range of the weights.



Mathematics
1 answer:
choli [55]2 years ago
3 0

Answer:

Apple

Orange

Step-by-step explanation:

Apple has the greater median with a median value of 150 which is more than that of orange at 130

The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.

Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.

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Answer:

10 minutes

Step-by-step explanation:

Since you can do 6 flyers each minute, the rate would go at 6x, with x being minutes. You initially did 80, so the equation for you would be y=6x+80.

Your friend's equation would be y=4x+100, because he initially had 100 done and is now getting 4 done per minute.

If you put the 2 equations in your calculator, the intersection will happen at x=10, showing that you and your friend will have an equal number of flyers at 10 minutes.

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2 years ago
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

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