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FinnZ [79.3K]
3 years ago
12

I think it’s A but I need help double checking!

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0
Yea it’s A good work
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I need help with this question
Alex787 [66]

Answer:

<h2>C</h2>

Step-by-step explanation:

using the pythagorian theorem, we know that a^2+b^2=c^2. inputting the numbers into this equation, we get

8^2+23^2=c^2

then, using our big math brains, we get 64+529=c^2

adding together the numbers, we end up with 593

just take the sqyare root of that and bada bing bada boom! you get 24.35, or 24.4, therefore the answer is C

3 0
3 years ago
What are the domain and range of f(x) = -37?
antiseptic1488 [7]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
OMG IM SO CONFUSED HELPPPP
Sunny_sXe [5.5K]

Answer:

5.4 is rational. 5.4 divide by 2 is 2.45 5.3 and 5 3 are irrational, as it cant be divided easily

8 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
How is 9.746 x 1013 written in standard form?
sammy [17]

Answer:

9872.698 is 9.746 x 1013 in standard form

4 0
4 years ago
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