Why do you divide by 2 for triangles and why do you divide by 3 for pyramids.

Mathematics

1 answer:

Setler79 [48]3 years ago

4 0

Answer:

Triangles are 2D shapes and Pyramids are 3D shapes

Step-by-step explanation:

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What are the subsets of the set {7, 8, 9}?

torisob [31]

The subsets of {7,8,9} are:
∅
{7}
{8}
{9}
{7,8}
{7,9}
{8,9}
{7,8,9}.

7 0

3 years ago

The difference between the roots of the equation 3x^2+bx+10=0 is equal to 4 1/3 . Find b.

telo118 [61]

$\textit{quadratic formula}\\
{{ 3}}x^2{{ +b}}x{{ +10}}=0
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
\\ \quad \\
meaning\implies x=\cfrac{-b\pm\sqrt{b^2-4(3)(10)}}{2(3)}\qquad now
\\ \quad \\
\cfrac{-b\pm\sqrt{b^2-4(3)(10)}}{2(3)}\to 
\begin{cases}
\cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)}
\\ \quad \\

\cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)}
\end{cases}\impliedby \textit{two roots}$

$\textit{and their root difference is }4\frac{1}{3}\implies \cfrac{13}{3}\qquad so
\\ \quad \\
\left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)} \right]-\left[ \cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)} \right]=\cfrac{13}{3}
\\ \quad \\
\left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{6} \right]+\left[ \cfrac{+b+\sqrt{b^2-4(3)(10)}}{6} \right]=\cfrac{13}{3}
\\ \quad \\
\cfrac{-b+\sqrt{b^2-4(3)(10)}+b+\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}
\\ \quad \\
\cfrac{2\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}$

and I'm pretty sure you can take it from there

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3 years ago

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Aleksandr-060686 [28]

B. 30
Rise over run
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3 years ago

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katrin2010 [14]

Answer:

A.26

B.116

C.64

Step-by-step explanation:

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3 years ago

Convert 9.3 kribs into grees given that 4.2 kribs = 18 grees.

maria [59]

Answer:

39.9 grees

Step-by-step explanation:

Since 4.2 kribs = 18 grees

Then,

1 krib = 18/4.2 grees

9.3 kribs = (18/4.2) x 9 3

9.3 kribs = 39.9 grees.

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3 years ago